Been trying to get past this but it just keeps building on each other. It's for tomorrow:
a) Find any vertical and horizontal asys
b) where axis are crossed
c) show curve has no turning points
d) sketch curve, labeling it properly.
e) sketch f(-x) on the graph.
So vertical asympotes are as simple as LCM equal to 0 and substitue. Vertical?!?
Axis cross should be x = 0 and y = 0. It is (0,0) so it should be solved like that.
Curve's turning points. I want to see if differentiating should be enough, or do i need to go down to and make it =0. If the answer is imaginary it's proved, correct?
sketching curve should be done using the information gained from the previous questions and finding out which side the curve goes when approaching the asymptotes (asy+0.0001), (asy - 0.00001) to get a quick estimate.
f(-x) means a reflection in the x axis? Thanks for the posts