Thread: Numerical Analysis: Newton's Method Problem

Use Newtons Method to find the solution accurate to within 10^-5 of the following problem.

x^2-2xe^(-x)+e^(-2x)=0

How do I know when to stop and how do I find P0 and P1?

Originally Posted by wvlilgurl

Use Newtons Method to find the solution accurate to within 10^-5 of the following problem.

x^2-2xe^(-x)+e^(-2x)=0

How do I know when to stop

as the problem said, you want to be accurate to 5 decimal places, so keep finding a better approximation until the first 5 decimal places do not change

and how do I find P0 and P1?

i suppose you mean the initial guess?

first note that you have

so a good initial guess would be one where is close to . in fact, it is an equivalent problem to solve . would be easier to run Newton's method on it too. you can use a graph to come up with a guess

Hope that helps