1. ## Polynomials

Locate the turning points of the curve y=x(x^2 - 12) and determine their nature.

2. Originally Posted by sprinterjr
Locate the turning points of the curve y=x(x^2 - 12) and determine their nature.
$y = x^3 - 12x$.

Solve $\frac{dy}{dx} = 0$ to get x-coordinates of stationary points.

Use the sign test to test the nature of each stationary point.

Substitute each solution for x back into $y = x^3 - 12x$ to get the corresponding y-coordinate.