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Math Help - Polynomials

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    Newbie sprinterjr's Avatar
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    Polynomials

    Locate the turning points of the curve y=x(x^2 - 12) and determine their nature.
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  2. #2
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    Quote Originally Posted by sprinterjr View Post
    Locate the turning points of the curve y=x(x^2 - 12) and determine their nature.
    y = x^3 - 12x.

    Solve \frac{dy}{dx} = 0 to get x-coordinates of stationary points.

    Use the sign test to test the nature of each stationary point.

    Substitute each solution for x back into y = x^3 - 12x to get the corresponding y-coordinate.
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