1. ## limits

1) the limit as x approaches -2 of x^3 + 2x^2/x^2 - 2x - 8

A) -2/3 B) 3/2 C) -1/8 D)DNE

2. Originally Posted by obsmith08
1) the limit as x approaches -2 of x^3 + 2x^2/x^2 - 2x - 8

A) -2/3 B) 3/2 C) -1/8 D)DNE
Note that $\frac{x^3+2x^2}{x^2-2x-8}=\frac{x^2\left(x+2\right)}{\left(x-4\right)\left(x+2\right)}$

Can you take it from here?

3. Originally Posted by obsmith08
1) the limit as x approaches -2 of x^3 + 2x^2/x^2 - 2x - 8

A) -2/3 B) 3/2 C) -1/8 D)DNE
$lim_{x \to -2} \frac{x^3+2x^2}{x^2-2x-8} = -\frac{2}{3}$