1. ## Logarithmic function

$F(x)=\int\limits_{2}^{x} \sqrt(3t^2+1)dt\$
Find F(2), F'(2), F''(2)
not really sure how to do this i thought every answer would be zero, since every integral is measured from 2 to 2... and everything in the parenthesis is under the sq rt

2. Originally Posted by vinson24
$F(x)=\int\limits_{2}^{x} \sqrt(3t^2+1)dt\$
Find F(2), F'(2), F''(2)
not really sure how to do this i thought every answer would be zero, since every integral is measured from 2 to 2... and everything in the parenthesis is under the sq rt

$F(x)=\int\limits_{2}^{x} \sqrt{3t^2+1}dt\$

$F(2) = 0$, yes..

$F'(x) = 3x^2+1$, Fundamental Thm of Calculus
and $F''(x) = ...$

3. thanks alot