Another integral

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January 29th 2009, 09:10 PM
dmac

Another integral

mmk so heres a indefinite integral. (2x-5)/(x^2+2x+2) I know I need to complete the square but im not sure as to what I do from there
January 29th 2009, 09:14 PM
Chop Suey

Quote:

Originally Posted by dmac

mmk so heres a indefinite integral. (2x-5)/(x^2+2x+2) I know I need to complete the square but im not sure as to what I do from there

By simple algebraic manipulations:
$\begin{aligned}<br /> \frac{2x-5}{x^2+2x+2} &= \frac{2x+2}{x^2+2x+2} - \frac{7}{x^2+2x+1+1}\\<br /> &= \frac{2x+2}{x^2+2x+2} - \frac{7}{(x+1)^2+1}<br /> \end{aligned}$

Which are two straightforward integrals.
January 29th 2009, 09:23 PM
dmac

thank you very much that helps so much! Its just hard to see that. guess I need to practice more! tyvm

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