Expand it & Simplify:

So we know the degree of the numerator is the same as the degree of the denominator

There is a vertical asymptote at x = 0 because 2x = 0 and therefore x = 0

Now we have an (x - 1) in the numerator and the denominator

This means we can cancel these out giving us a point of discontinuity at x = 1

Now sub it back into the equation with the (x - 1) removed

Therefore there is a point of discontinuity at the point (1,1)

Hope this helps : )