So I have a problem that I have all parts figured out except for the final part of the question.
The function is f(x)=(x^2 - 1) / (2x^2 - 2x).
The function is discontinuous at 0 and 1.
x=0 is a vertical asymptote.
The horizontal asymptote is y=1/2
Now the final part of the question is: Since there is only one vertical asymptote, indicate on the graph what occurs at the other point of discontinuity. Be specific by giving numerical values.
I am really unsure what happens here. Does the point not exist? I'm confused Any help would be appreciated