Hello, jsu03!
You're doing fine . . .
I let: .
So: . . . . . Good!
The new integral is: .
Now let:
Got it?
Can someone help me with this problem? I already started it but got stuck. Thanks.
1. Integral sin^-1 xdx
I let u=sin^-1x dv=dx
du=dx/squareroot 1-x^2 v=x
so integral sin^-1 xdx = x(sin^-1x)-integral x dx/squareroot 1-x^2.....