For y=(1/4)x^4-(2/3)x^3+(1/2)x^2-3 find the exact intervals on which the function is:
c) concave up
d) concave down
Then find any
e) local extreme values
f) inflection points
I graphed this and came up with the following answers:
a) (0, infinity)
b) ( -infinity, 0)
c) (-infinity, infinity)
e) Min: -3 at x=0
Does that look right?
aren't you supposed to use information from the first and second derivatives to analyze the function, rather than just looking at a graph?
Ok so x^3-2x^2+x would be the first derivative...
and the second one would be 3x^2-4x+1 ?
I still don't know how to do it without graphing...but I guess I could graph those two?
have you learned about the first and second derivative tests and what they can tell you about a function?