Area under a curve [please confirm this]

**db5vry** · January 29th 2009, 05:41 AM

Can you tell me if this is right? Thanks for looking

**Krizalid** · January 29th 2009, 06:05 AM

A certain function must be integrated on $[2,3].$ One can check that $f(x)\ge g(x)$ on that interval where $f$ and $g$ are respectively the functions.

So the integral which gives the expected area is $\int_{2}^{3}{\left( 5x-4-{{x}^{2}}-2 \right)\,dx}=\frac{1}{6},$ which is the same answer you got.

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