NOTE: I use ( as the beggining intergral sign... so ( x^2 dx is the integral of x^2.
1.I have two integrals. (tan x sec^2 x dx and (sin x / cos^3 x dx
-after looking at them I realize they are the same thing...
-then why do i get different answers?
1) u =tan x du=sec^2 x dx ((u)du = u^2 /2. Answer is (tan^2 x/2) + C
2) u =cosx du=-sinx dx -du=sinx dx (-du/(u)^3= (u)^-2/2. Answer is (sec^2 x)/2 + C
What am I doing wrong?
2. (tan(3x) dx
- I got the answer -1/3 ln cos(3x) +C. I was wondering if I should an absolute value around COS 3x or not. Should I?
3.( x(2+x)^.5 dx
-how do i do this one?
- this is how far i got. u= 2+x du=1 ( du(x) (u)^.5 I am lost now.
-Thanks for the help in advance
For #2, I believe you should have absolute value since you are talking about .
For #3, with your choice of u,
since , . Thus
I believe you can take it from here.