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Math Help - Calculus Derivatives

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    Arrow Calculus Derivatives

    Find dy/dx, where y = ((x+2)(x+4))/(x-1)
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  2. #2
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    Quote Originally Posted by SoYah View Post
    Find dy/dx, where y = ((x+2)(x+4))/(x-1)
    The key here is the quotient rule:
    \frac{d}{dx}\frac{f(x)}{g(x)}=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}

    Since y = \frac{(x+2)(x+4)}{(x-1)}=\frac{x^2+6x+8}{(x-1)},

    we have \frac{dy}{dx}=\frac{[(x^2+6x+8)'](x-1)-(x^2+6x+8)[(x-1)']}{(x-1)^2} =\frac{(2x+6)(x-1)-(x^2+6x+8)(1)}{(x-1)^2}=...

    I believe you can take it from here.
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