If f(x) = x^2 - (the absolute value of x-4), is the behavior of f at x=4 a cusp or a corner?
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If f(x) = x^2 - (the absolute value of x-4), is the behavior of f at x=4 a cusp or a corner?
Does anyone have a calculator they could figure this out on real quick? Mine won't do absolute values...
Draw y = x^2 and y = -|x - 4|.Quote:
Originally Posted by SoYah
Now use addition of ordinates to draw the graph of y = x^2 - |x - 4| by hand.
The answer will now be clear.