Take your position to be (0,0), and the point where the car is closest to you

(that is right infront of you) to be (132,0), and take this to occur at time

t=0.

Then the position of the car atime t is (132, 264t). Then the camera angle

theta (measured from the position of the car at t=0) satisfies:

tan(theta) = 264t/132=2t.

so:

d/dt(tan(theta)=2

Therefore:

sec^2(theta) dtheta/dt = 2,

or:

dtheta/dt = 2 cos^2(theta).

Now at t=0, theta=0, so dtheat/dt=2 radians/s = 2*180/pi degrees/s

When t=0.5 theta=pi/4, so dtheat/dt=2 cos^2(pi/4)= 1 radian/s = 180/pi degrees/s.

RonL