(that is right infront of you) to be (132,0), and take this to occur at time
Then the position of the car atime t is (132, 264t). Then the camera angle
theta (measured from the position of the car at t=0) satisfies:
tan(theta) = 264t/132=2t.
sec^2(theta) dtheta/dt = 2,
dtheta/dt = 2 cos^2(theta).
Now at t=0, theta=0, so dtheat/dt=2 radians/s = 2*180/pi degrees/s
When t=0.5 theta=pi/4, so dtheat/dt=2 cos^2(pi/4)= 1 radian/s = 180/pi degrees/s.