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Math Help - absolute value/calculus

  1. #1
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    absolute value/calculus

    Here is the question I'm having trouble with. Apparently the answer is A.

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  2. #2
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    Quote Originally Posted by scorpion007 View Post
    Here is the question I'm having trouble with. Apparently the answer is A.

    You need to find the derivative at x=k
    But, the trick is that this an absolute value function.
    The regular sine is negative in that interval
    So you need to find the derivative of,
    y=-\sin x
    y'=-\cos x
    At, k:
    -\cos k
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  3. #3
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    ah, thank you very much. That explains things.
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