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Math Help - Chain rule

  1. #1
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    Exclamation Chain rule

    Use the chain rule ti find f '(x) when f (x) is given by

    (a) (2x^2 - 3x + 1)^5

    (b) (2x^3 - 1)^-2/3

    (c) cosec x

    It would be great if you could explain the steps as well, because from my notes, it's not making a whole lot of sense

    cheers in advance
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  2. #2
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    Quote Originally Posted by scott.b89 View Post
    Use the chain rule ti find f '(x) when f (x) is given by

    (a) (2x^2 - 3x + 1)^5

    (b) (2x^3 - 1)^-2/3

    (c) cosec x

    It would be great if you could explain the steps as well, because from my notes, it's not making a whole lot of sense

    cheers in advance
    Ok you bring the power to the front and take 1 away like normal differentiation. You then multipply it by whatever is in the bracket differentiated.

    so a would be 5(2x^2 - 3x + 1)^4 *(4x-3)

    =(20x-15)(2x^2 - 3x + 1)^4

    i think that right

    try it with b

    for c i think you just have to know that cosecx is -cosecxcotx
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