Find the volume of the solid obtained by rotating the region bounded by the graphs of y=x^(2) and x=y^(2) around the line x=-1. Thanks for the help.
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using cylindrical shells w/r to x ... $\displaystyle V = 2\pi \int_0^1 (x+1)(\sqrt{x} - x^2) \, dx $ using washers w/r to y ... $\displaystyle V = \pi \int_0^1 (\sqrt{y} + 1)^2 - (y^2 + 1)^2 \, dy$
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