alternatively, you could use a trig substitution. let
im still confused, how would i use this http://www.mathhelpforum.com/math-he...48c6e6bb-1.gif) or http://www.mathhelpforum.com/math-he...b444a9c7-1.gif
hey Jhevon you a Jamaican man...bless i from st. kitts
yes just not at this level of difficulty
for my method:
so our integral becomes:
this simplifies to
now can you finish up? don't forget this is a definite integral, so you have to deal with the limits at some point
hope its clear!
Don't complicate to much, note that,
you`re right my friend,
but luckily all roads lead to Rome.
i`m not too much familiar with the subject,which explains the length :]