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- January 27th 2009, 04:49 PMsobadinevaluate definite integral
- January 27th 2009, 07:05 PMKrizalid
Put

- January 27th 2009, 07:08 PMJhevon
alternatively, you could use a trig substitution. let

- January 27th 2009, 07:17 PMsobadinumm
im still confused, how would i use this http://www.mathhelpforum.com/math-he...48c6e6bb-1.gif) or http://www.mathhelpforum.com/math-he...b444a9c7-1.gif

hey Jhevon you a Jamaican man...bless i from st. kitts - January 27th 2009, 07:28 PMJhevon
- January 27th 2009, 07:42 PMsobadin
yes just not at this level of difficulty

- January 27th 2009, 07:47 PMJhevon
the important thing is to be able to recognize when you can use it. the method is essentially the same in all cases.

for my method:

so our integral becomes:

this simplifies to

now can you finish up? don't forget this is a definite integral, so you have to deal with the limits at some point - January 27th 2009, 09:00 PMbecker89
hope its clear!

- January 27th 2009, 09:11 PMKrizalid
Don't complicate to much, note that,

- January 27th 2009, 09:20 PMbecker89
you`re right my friend,

but luckily all roads lead to Rome.

i`m not too much familiar with the subject,which explains the length :]