Hi, am doing a question looking for the length of a curve, the function given is $\displaystyle y=e^x + 1/4e^-x$, from $\displaystyle [1,0]$ is my interval.

I got all the parts down i got $\displaystyle dy/dx=e^x-1/4e^-x $then from the length of curve formula,

$\displaystyle L = \int\ {\sqrt{1 + (e^x -1/4e^x)^2}}$

my problem is the integral under the square root, i tried substitution i tried parts i couldnt get anything, any clues on how to start off this integral. Thank You