please help! any tips or help would be awesome. ive gotten through part of the problem, but get lost.

$\displaystyle \int\frac{\sqrt{x^2-9}}{x}dx\\$

$\displaystyle x=3\sec\Theta\\$

$\displaystyle dx=3\sec\Theta\tan\Theta\ d\Theta$

$\displaystyle \int\frac{\sqrt{3\sec^2\Theta-9}}{3\sec\Theta}\cdot3\sec\Theta\tan\Theta\ d\Theta$

-clay