# Math Help - More Finite Math help

1. ## More Finite Math help

Okay so I stumbled upon this question and I think I may be on the right track but request backup..

A store handles a specialty item that has a marginal cost of $24 and a fixed cost of$360. The sales required to break even are 75 items.

A) Find the linear cost function
My answer was --> c(x) = 24+360

B) Find the linear revenue function
My answer was --> R(x) = px -->R(x) = 384x

Does this look correct?

2. Originally Posted by johnewton
Okay so I stumbled upon this question and I think I may be on the right track but request backup..

A store handles a specialty item that has a marginal cost of $24 and a fixed cost of$360. The sales required to break even are 75 items.

A) Find the linear cost function
My answer was --> c(x) = 24+360
nope, it should be 24x + 360

B) Find the linear revenue function
My answer was --> R(x) = px -->R(x) = 384x

Thank you math scholars!!
nope.

break even means $C(x) = R(x)$

so, the problem says $C(75) = R(75)$

now, $C(75) = 2160$, and $R(x) = ax \implies R(75) = 75a$

now, set up the equation to solve for $a$, then you can find your revenue funciton

3. Originally Posted by johnewton
Okay so I stumbled upon this question and I think I may be on the right track but request backup..

A store handles a specialty item that has a marginal cost of $24 and a fixed cost of$360. The sales required to break even are 75 items.

A) Find the linear cost function
My answer was --> c(x) = 24x+360

did you forget the x ?

B) Find the linear revenue function
My answer was --> R(x) = px -->R(x) = 384x

R(x) = C(x) at the break even point

p = selling price

75p = 24(75) + 360

p = 28.80

R(x) = px = 28.80x

ok?

4. ## I

thank you for the help!!

5. ## Got it

to solve for "A" you just divide 2160 by 75 which gives you 28.80. I love this website! Thank you Jhevon and Skeeter!

6. Originally Posted by johnewton
to solve for "A" you just divide 2160 by 75 which gives you 28.80.
yup, just as skeeter did

I love this website!
....um, we...love you too?? ...ok, that was awkward

Thank you Jhevon and Skeeter!
you're welcome

take care