What is .693?. It's ln(2). See now?.
I'm having trouble figuring this one out:
when f(x)=1/x between the interval [1,2]
I keep on getting 1/infinity and that's zero, but the correct answer is appr. .693. thank you
Note: its actually the summation of f(xsubi)*change in x but (2-1)/n is 1/n so i simplified it