Find the limit by using the l' Hopital's rule! \lim_{x\to0}\frac{\cos\!\left(x\right)-1}{2x^2} So far i got to \lim_{x\to0}\frac{\-sin\!\left(x}{4x} What do you do next
Follow Math Help Forum on Facebook and Google+
Originally Posted by Emmeyh15@hotmail.com Find the limit by using the l' Hopital's rule! \lim_{x\to0}\frac{\cos\!\left(x\right)-1}{2x^2} So far i got to \lim_{x\to 0}\frac{\-sin\!\left(x}{4x} What do you do next Tell your teacher that it is Bernoulli's rule actually.
Last edited by courteous; Jan 23rd 2009 at 09:31 AM. Reason: Bernoulli
Originally Posted by courteous Tell your teacher that it is Bernoulli's rule actually. But is you call it Bernoulli's rule most (if not all) people won't know what your talking about. Here's an interesting site. Calculus I Notes, Section 4-5
View Tag Cloud