dy/dx = (x^2)+(8y^2)/(3xy)? I know that you have to name a parmater v that takes the value y/x and substitute it back in but I'm lost after that.
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Originally Posted by lord12 dy/dx = (x^2)+(8y^2)/(3xy)? I know that you have to name a parmater v that takes the value y/x and substitute it back in but I'm lost after that. What is it you are trying to do to this expression? Integrate it? Differentiate it?
Originally Posted by lord12 dy/dx = (x^2)+(8y^2)/(3xy)? I know that you have to name a parmater v that takes the value y/x and substitute it back in but I'm lost after that. If your differential equation is You can do a number of things. First the equation is homogeneous so if you let as you have said, then then , substitute giving can x's from the right and solve for v' giving something that is separable. The equation is also Bernoulli.
Ahh. I see. Your equation can be written: Which gives: Giving: Hence Hence:
how do you write this in terms of x and y?
Originally Posted by lord12 how do you write this in terms of x and y? First you solve it for v as a function of x. Then you replace v with y/x.
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