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Thread: Integration

  1. Jan 22nd 2009, 11:30 AM #1
    Haris
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    Integration

    \int \frac{e^x}{1+e^{2x}}

    Could someone explain how to solve this?
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  2. Jan 22nd 2009, 11:33 AM #2
    galactus
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    Make the sub u=e^{x}, \;\ du=e^{x}dx

    After making the subs, the resulting integral should look familiar and a cakewalk from there on out.
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  3. Jan 22nd 2009, 11:34 AM #3
    Jester
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    Quote Originally Posted by Haris View Post
    \int \frac{e^x}{1+e^{2x}}\,

    Could someone explain how to solve this?
    \int \frac{e^x}{1+e^{2x}}\,dx (note the dx - it's important)

    Try letting u = e^x
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  4. Jan 22nd 2009, 11:46 AM #4
    Haris
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    I=tan^{-1}(e^x)

    Is that correct?
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  5. Jan 22nd 2009, 11:57 AM #5
    Jester
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    Quote Originally Posted by Haris View Post
    I=tan^{-1}(e^x) + c

    Is that correct?
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