$\displaystyle \int \frac{e^x}{1+e^{2x}}$ Could someone explain how to solve this?
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Make the sub $\displaystyle u=e^{x}, \;\ du=e^{x}dx$ After making the subs, the resulting integral should look familiar and a cakewalk from there on out.
Originally Posted by Haris $\displaystyle \int \frac{e^x}{1+e^{2x}}\, $ Could someone explain how to solve this? $\displaystyle \int \frac{e^x}{1+e^{2x}}\,dx $ (note the dx - it's important) Try letting $\displaystyle u = e^x$
$\displaystyle I=tan^{-1}(e^x)$ Is that correct?
Originally Posted by Haris $\displaystyle I=tan^{-1}(e^x) + c$ Is that correct?
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