Originally Posted by

**Dana_Scully** Find the area of the region enclosed by $\displaystyle y=x^2-5x$ and $\displaystyle y=x+7$.

What I did was:

$\displaystyle \displaystyle\int^7_{-1} (x+7)-(x^2-5x) dx$

$\displaystyle \frac{-x^3}{3}+\frac{6x^2}{2}+7$ from -1 to 7 (sorry, not sure how to type that)

$\displaystyle \left(-\frac{343}{3}+147+7\right) - \left(\frac{1}{3}+3-7\right)$

Area = $\displaystyle \frac{130}{3}$

This is what I got, but our computer program tells me that I am wrong. Is there a mistake I'm making?