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Math Help - Evaluate the Integral

  1. #1
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    Question Evaluate the Integral

    \int_0^3{\,3dx/(x+1)}

    How can I find the antiderivative of 3dx/(x+1)?
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  2. #2
    Senior Member vincisonfire's Avatar
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    Let *u = (x+1) \implies du = dx \implies [0,3] \implies [1,4] *
    <br /> <br />
3\int_1^4{\frac{du}{u}} = 3ln(4)-3ln(1) = 3ln(4) = ln(64)<br />
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  3. #3
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    Question

    I know how to evaluate the integral, I just want to know how to get the antiderivative of 3dx/(x+1)...
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  4. #4
    Member javax's Avatar
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    Quote Originally Posted by katchat64 View Post
    I know how to evaluate the integral, I just want to know how to get the antiderivative of 3dx/(x+1)...
    U know that the derivative of \ln x=\frac{1}{x} so in this case the antiderivative of \frac{3}{x+1} is 3\ln(x+1)
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  5. #5
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    Thumbs up

    Thank you, that's more of an elaborate explanation.
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