Find $\displaystyle \int_{1}^{5} f(x)dx$ if $\displaystyle \int_{0}^{1} f(x)dx = -2.6$ and $\displaystyle \int_{0}^{5} f(x)dx = 1.5$

I know for this question we do:

$\displaystyle \int_{0}^{5} f(x)dx = \int_{0}^{1} f(x)dx + \int_{1}^{5} f(x)dx$

Which rearranged turns into:

$\displaystyle \int_{1}^{5} f(x)dx = \int_{0}^{5} f(x)dx - \int_{0}^{1} f(x)dx$

But I do not know what I am to do...

Thanks : )