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Math Help - I haven't the slightest idea how to solve this

  1. #1
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    I haven't the slightest idea how to solve this

    I need to solve for this but I don't know how (i've probably forgot)

    cos4x=sin4x
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  2. #2
    Senior Member vincisonfire's Avatar
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     \frac{sin(4x)}{cos(4x)} =1

     tan(4x) =1

     4x =arctan(1) = \frac{\pi}{4} + n\pi where  n \in \mathbb Z

     x = \frac{\pi}{16} + \frac{n\pi}{4}
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  3. #3
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    Perhaps I should broaden the question:

    I have to find the area between the two curves
    f(x)=sin(4x) and g(x)=cos(4x) for <br />
x = \frac{\pi}{2} ≤ x ≤ 0
    Now, from what I understand, I need to find where the graphs intersect in order to determine which function need to become absolute. Is this step necessary at all?
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