if f(x) is an even function prove that f'(x) is odd function
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It's quite simple since now just differentiate.
It's quite simple since now just differentiate. krizalid you make a mistake its an even function so f(-x)=f(x), now differentiate -f'(-x)=f'(x) f'(-x)=-f'(x) hence, f'(x) is an odd function
I let myself go with the word "odd," haha; anyway, the idea is the same.
Alternatively So
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