Help! Hey guys, please help me out in this word problem:
So far... this is by solution.Carlo is perched precariously on top of a 10-foot ladder leaning against the back wall of an apartment building (spying on an enemy of his) when it starts to slide down the wall at a rate of 4 ft per minute. Carlo's accomplice, Alex, is standing on the groud 6 ft. away from the wall, with the bottom of the ladder between the wall and Alex. How fast is the base of the ladder moving when it hits Alex?
dy/dt = 4
x = 6
and my equation is (but obviously wrong):
x^2 + y^2 = 10^ / 100.
6^2 + y^2 = 100
y^2 = 100-36
y = 8
But i don't really know what to do afterwards... Please help me out!
Hello, anfieldgirl!
Sounds like "Home Alone" . . .
Carlo is perched precariously on top of a 10-foot ladder leaning
against the back wall of an apartment building (spying on an enemy of his)
when it starts to slide down the wall at a rate of 4 ft per minute.
Carlo's accomplice, Alex, is standing on the ground 6 ft away from the wall.
How fast is the base of the ladder moving when it hits Alex?Code:| * |\ | \ | \ y | \ 10 | \ | \ | \ * - - - * - - * x A
We are given: . ft/min.
We know that: .
Differentiate with respect to time: .
When
So we have: .
The base of the ladder hits Alex at ft/min.