Which is the easiest method to find the antiderivative of (2t-3).
I know that this may be an easy one, I just need to see ways of finding out how to find an antiderivative.
If you're a beginner, it helps to write every term (if possible) in the form
$\displaystyle ax^n$.
Then you can remember that the antiderivative is
$\displaystyle \frac{a}{n + 1}x^{n + 1} + C$.
So in this case, you'd have $\displaystyle 2t^1 + 3t^0$.
Can you find this antiderivative using the formula?
If you're finding a definite integral, once you have the antiderivative, substitute the upper limit and see what you have ($\displaystyle F(b)$, substitute the lower limit ($\displaystyle F(a)$) and see what you have, then do $\displaystyle F(b) - F(a)$.