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Originally Posted by katchat64 Recall that And if then . Just substitute the correct values.
I thought that you were suppose to take the antiderivaitve of 5x and then substitute in 0 & 2. Is that what you meant?
Originally Posted by katchat64 I thought that you were suppose to take the antiderivaitve of 5x and then substitute in 0 & 2. Is that what you meant? Yes, that's exactly what I meant. It helps if you learn what the terminology means before you ask how to do something.
Originally Posted by katchat64 I thought that you were suppose to take the antiderivaitve of 5x and then substitute in 0 & 2. Is that what you meant? Yes:
Well that kinda got me confused, but it doesn't hurt to know the terminology. Thanks.
I have one more question for you. How did you get the numbers on the integral sign, the ones that tell you the range.
Originally Posted by katchat64 I have one more question for you. How did you get the numbers on the integral sign, the ones that tell you the range. The code is \int_a^b{integrand\,dx} where a is your lower limit and b is your upper.
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