Hello, desdemoniagirl!
Your suspicions are correct . . .
We have: .
Make two fractiions: /
. . and we have: .
And now you can integrate: . . . . . right?
here is an integral that is just driving me nuts.
Integral (cosx+sinx)/(sin2x) dx. I think that I am supposed to use the duoble angle formula for the bottom part, but im supposed to take the integral to completion, as in a final answer with +c at the end. I hope someone can help. Thanks
There are standard results for the integrals of those two trignometric functions:
But if you're not familiar with these and want to work it out from first principles, then have a look at these:
Integral sec(x)
Integral csc(x)
I really appreciate the help that you both gave to me earlier. Again thanks soooooooo much. I have another one or two i am still stuck on, here they are and I really hope that you can help. Thanks in advance.
Integral (cosx)/(Square root(1+sin^2(x)))
Integral (1/(x+a)(x+b))