Is there anyway to nontrivially decompose

$\displaystyle \frac{1}{(x-2)^2}$

into partial fractions?

Thanks.

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- Jan 20th 2009, 11:00 AMsoloakewlstickpartial fractions
Is there anyway to nontrivially decompose

$\displaystyle \frac{1}{(x-2)^2}$

into partial fractions?

Thanks. - Jan 20th 2009, 11:08 AMHaris
$\displaystyle \frac{1}{(x-2)^2}=\frac{A}{(x-2)}+\frac{B}{(x-2)^2}$

- Jan 20th 2009, 01:45 PMKrizalid
I see no good reason to turn that into partial fractions. What's the main purpose?