hi, can someone show me why $\displaystyle sin(3x)/2x$ = 3/2? is it because they multiplied $\displaystyle sinx/x$ by 3/2? if so why does 3sinx = sin3x??

Printable View

- Jan 19th 2009, 08:28 PMArezLimit of a trig functions
hi, can someone show me why $\displaystyle sin(3x)/2x$ = 3/2? is it because they multiplied $\displaystyle sinx/x$ by 3/2? if so why does 3sinx = sin3x??

- Jan 19th 2009, 08:43 PMmr fantastic
- Jan 19th 2009, 09:37 PMArez
on that note then, how would I do $\displaystyle sin^2(3t)/2t$? the squared is throwing me off..

- Jan 19th 2009, 09:42 PMchiph588@
First off I think a new thread is in order but...

$\displaystyle \lim_{x \to 0} \frac{\sin^2 (3x)}{2x} = \left( \lim_{x \to 0} \sin(3x) \right) \cdot \left( \lim_{x \to 0} \frac{\sin(3x)}{2x} \right) \; \; ...$