for x=(e^t) -1 y=e^2t Is this a case of using natural logs to find t and substitute it into one of the equations?
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Originally Posted by sfgiants13 for x=(e^t) -1 y=e^2t Is this a case of using natural logs to find t and substitute it into one of the equations? It's not really necessary. From the first $\displaystyle e^t = x+1$ the second $\displaystyle y = e^{2t} = \left(e^t \right)^2 = (x+1)^2$
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