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Math Help - integration with arctan

  1. #1
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    integration with arctan

    integrate:

    8 / (x-2)^2 dx

    i tried to expand to

    8 / (x^2 + 4 -4x) and then substitute x = tan theta .... but i got nowhere
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  2. #2
    o_O
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    No need for trigonometric subsitution. Simply let: u = x - 2 \ \Rightarrow \ du = dx

    So our integral becomes: 8 \int \frac{1}{(x-2)^2} \ dx = 8 \int \frac{1}{u^2} \ du
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