Use the bisection methos to find solutions accurate to within 10^-2 for x^3-7x^2+14x-6=0 for each interval [0,1],[1,3.2],[3.2,4]. I don't know how to find the number of iterations necessary for each interval. Thanks!
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Originally Posted by wvlilgurl Use the bisection methos to find solutions accurate to within 10^-2 for x^3-7x^2+14x-6=0 for each interval [0,1],[1,3.2],[3.2,4]. I don't know how to find the number of iterations necessary for each interval. Thanks! The interval length is halved at every iteration so after n steps the inteval length is where is the initial interval length. So if we want the -th interval to be less than or equal we need: .
Last edited by Constatine11; Jan 19th 2009 at 12:27 PM.
for the interval [0,1] they get 7 for the interval [1,3.2} they get 8 I got the first one at 7 but I cannot get 8 for the second one. DO you knwo how they got 8?
Originally Posted by wvlilgurl for the interval [0,1] they get 7 for the interval [1,3.2} they get 8 I got the first one at 7 but I cannot get 8 for the second one. DO you knwo how they got 8? In case 2 we have , so we seek an integer n such that: which we can use trial and error to find that the smallest integer such that this holds is .
Last edited by Constatine11; Jan 19th 2009 at 12:46 PM.
still dont get it. I get 6
Originally Posted by Constatine11 In case 2 we have , so we seek an integer n such that: which we can use trial and error to find that the smallest integer such that this holds is . Put so Put so .
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