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**ronaldo_07** Sketch the direction field of the differential equation

y′ = 2 − 3y + $\displaystyle y^2$

in the domain $\displaystyle x \epsilon$[0, 3], $\displaystyle y \epsilon$[−3, 3].

Using the direction field decide whether a solution y(x) tends to a finite limit when $\displaystyle x\rightarrow\infty$.

How does this limit depend on the value of the initial condition y(0) ?

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Im not sure how to get the values to draw this directional field. Do I just sub in y=-3.-2.-1.0.1.2.3 ? and why do I have the domain of x when there is no x in the equation?