i think i have to do this
given, x = 0.2e^-0.1t
solve: A = integral (from 0 to tmax) of xdt
given y = 0.0909 + 0.00002x - 0.000000001x^2
solve: B = m*integral (from 100 to 500) of ydT
SORRY FOR INCONVENIENT TYPING
Do you mean:
If so then:
...............
This last, do you mean:given y = 0.0909 + 0.00002x - 0.000000001x^2
solve: B = m*integral (from 100 to 500) of ydT
SORRY FOR INCONVENIENT TYPING
you seem to have a confusing set of variables in what you have written.
............
RonL