i think i have to do this

given, x = 0.2e^-0.1t

solve: A = integral (from 0 to tmax) of xdt

given y = 0.0909 + 0.00002x - 0.000000001x^2

solve: B = m*integral (from 100 to 500) of ydT

SORRY FOR INCONVENIENT TYPING

Printable View

- October 25th 2006, 07:44 PMsamsumIntegration
i think i have to do this

given, x = 0.2e^-0.1t

solve: A = integral (from 0 to tmax) of xdt

given y = 0.0909 + 0.00002x - 0.000000001x^2

solve: B = m*integral (from 100 to 500) of ydT

SORRY FOR INCONVENIENT TYPING - October 26th 2006, 02:09 AMCaptainBlack
Do you mean:

If so then:

...............

Quote:

given y = 0.0909 + 0.00002x - 0.000000001x^2

solve: B = m*integral (from 100 to 500) of ydT

SORRY FOR INCONVENIENT TYPING

you seem to have a confusing set of variables in what you have written.

............

RonL