Domain of f(x)=sqrt(1+2x)

1+2x>=0

x>=-1/2

domain:: (-1/2,+inf)

and

domain of f '(x)=1/sqrt(1+2x).........do not understand to do this one..

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- October 25th 2006, 02:34 PMgracydomain of derivative
Domain of f(x)=sqrt(1+2x)

1+2x>=0

x>=-1/2

domain:: (-1/2,+inf)

and

domain of f '(x)=1/sqrt(1+2x).........do not understand to do this one.. - October 25th 2006, 03:08 PMSoroban
Hello, Gracy!

A minor (but important) change in your first answer . . .

Quote:

Domain of

Domain: .

. . . . . . . ↑

We__include__the

Quote:

Domain of

That prime-mark is distracting, but we can ignore it.

Since is under a square root, it must be positive or 0.

But since it is in the denominator, it cannot equal 0.

Hence, we have: .

Domain: .

- October 25th 2006, 05:34 PMThePerfectHacker
Basically whenever you have a continous function on [a,b] and differenciable at (a,b) then the derivative does not exist at 'a' and 'b'. Do you see why? One of the conditions that implies a function is not differenciable is when it fails to be countinous. Note whenever you have a continous function on [a,b] then it is continous from the right at 'a' and continous from the left at 'b' but it is not fully continous.