Trying to figure out the derivative of arctan(x/y)
Thank you Very much
ViperRobK
if we take the partial derivative with respect to x, we would get:
$\displaystyle \frac{\partial}{\partial x} \arctan \left( \frac{x}{y} \right) $
$\displaystyle =\frac{1}{1+(x/y)^2} \times \frac{1}{y} = \frac{1}{y+x^2/y} = \frac{y}{y^2+x^2}$ so your solution is correct.