I bet you forgot your integration constant?.
Now, try your t=.5 and t=1.5
I have this question:
1. The amount a fish grows follows the differential equation
,
with initial condition L(0) = 5, where t is measured in years and L is measured in centimetres. How much does the fish grow between ages t = 0.5 and t = 1.5?
(Give your answer to two decimal places.)
I integrated it to and did the definite integral calculation getting ~6cm. However, when I sub in L(0), I don't get 5. Is that relevant?