Find dy/dx at point (1,2) if y^3 sqrt(x)-3x^2y=2.
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Originally Posted by gracy Find dy/dx at point (1,2) if y^3 sqrt(x)-3x^2y=2. Implicit differentiation: d/dx[y^3 sqrt(x) -3 x^2 y = 0] so: 3 y^2 dy/dx sqrt(x) + y^3 (1/2)/sqrt(x) - 3 x^2 dy/dx = 0 so: dy/dx [3 y^2 sqrt(x) - 3 x^2] +y^3/(2 sqrt(x)) = 0 and Bob's your uncle. RonL
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