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Math Help - Urgent!

  1. #1
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    Urgent!

    Who can help me to understand the right and left limits?
    These are the functions: f(x)=(3x-2)/x*2 (a=-3 and 3)
    f(x)=x*2/!x! (a=0)
    Thank you
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  2. #2
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    Quote Originally Posted by blertta View Post
    Who can help me to understand the right and left limits?
    These are the functions: f(x)=(3x-2)/x*2 (a=-3 and 3)
    f(x)=x*2/!x! (a=0)
    Thank you
    Are your functions

    f(x) = \frac{3x-2}{2 x} and f(x) = \frac{2 x}{|\,x\;|}?
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  3. #3
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    Quote Originally Posted by danny arrigo View Post
    Are your functions

    f(x) = \frac{3x-2}{2 x} and f(x) = \frac{2 x}{|\,x\;|}?
    x*2 means 2 is the exponent
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  4. #4
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    Quote Originally Posted by danny arrigo View Post
    Are your functions

    f(x) = \frac{3x-2}{2 x} and f(x) = \frac{2 x}{|\,x\;|}?
    No,x*2 means 2 is the exponent.
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  5. #5
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    Quote Originally Posted by blertta View Post
    x*2 means 2 is the exponent
    So they're \frac{3x - 2}{x^2} and \frac{2x}{|x|}.


    First, are the functions discontinuous at the points in which you're trying to find the left and right hand limits? If not, then you can just substitute the value in and left hand limit = right hand limit.

    If so, then it will probably help you to draw a graph or table of values near the point you're trying to find the limits of, and say what you see it approaching from the right and from the left.
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