Use l' Hopital's Rule to find the limit. Show your work. Lim cosx-1/2x^2 is 0/0 form x->0
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Originally Posted by Emmeyh15@hotmail.com Use l' Hopital's Rule to find the limit. Show your work. Lim cosx-1/2x^2 is 0/0 form x->0 Please a bit clearer on your notation. Is this what you mean?
Yes sorry i didnt know how to make that arrow!!!
Originally Posted by Emmeyh15@hotmail.com Yes sorry i didnt know how to make that arrow!!! In applying L'Hopitals rule, you need to differentiate both numerator and denominator of the limit. Thus we see that Again, this limit has the indeterminate form So, I leave it for you to apply the rule one more time. Does this make sense?
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