Use the implicit differentiation to find dy/dx ( WORK OUT)

x^2 cosy-y^2=e^2x

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- Jan 13th 2009, 06:55 AM #1

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- Jan 13th 2009, 07:00 AM #2
Hint:

-- Use product rule between the $\displaystyle x^2$ and $\displaystyle \cos(y)$ terms.

-- keep in mind that $\displaystyle \frac{\,d}{\,dx}\left[f\left(y\right)\right]=f^{\prime}\!\left(y\right)\cdot\frac{\,dy}{\,dx}$.

-- $\displaystyle \frac{\,d}{\,dx}e^{ax}=ae^{ax}$

After you differentiate both sides, gather the $\displaystyle \frac{\,dy}{\,dx}$ terms together. From there, it should be easy.

Can you try to do the problem now?

- Jan 13th 2009, 07:04 AM #3

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