WORK OUT!
Use Newton's method to solve cos(3x)-2x+1=0. Show the values of each iteration until you have reached the " best" solution your calculator can display
Hi
Let f(x) = cos(3x)-2x+1 with a representative curve Cf
Start from say $\displaystyle x_0 = 0$
Then $\displaystyle x_1$ is the abscissa of the intersection point between the x axis and the tangent to the curve Cf at the point whose abscissa is $\displaystyle x_0$
f'(x) = -3 sin(3x)-2
The equation of the tangent to Cf at the point of abscissa $\displaystyle x_n$ is
$\displaystyle y = (-3 sin(3 x_n) - 2) (x - x_n) + cos(3 x_n) - 2 x_n + 1$
$\displaystyle x_{n+1}$ is given by
$\displaystyle 0 = (-3 sin(3 x_n) - 2) (x_{n+1} - x_n) + cos(3 x_n) - 2 x_n + 1$
$\displaystyle x_{n+1} = x_n + \frac{cos(3 x_n) - 2 x_n + 1}{3 sin(3 x_n) + 2}$
Start for example from $\displaystyle x_0 = 0$ and then use a calculator to iterate and find the best estimation of the solution